Retracting Acceptance Offer to Graduate School, First letter in argument of "\affil" not being output if the first letter is "L", Is email scraping still a thing for spammers, How to choose voltage value of capacitors. But this is simple! A seesaw is binary. You cant solve this puzzle? The riddle, as you'll recall, is this: There are twelve men on an island. Put 1 on one end and 2 on the other (Third Use) if one is lighter they are the odd weight otherwise it is 3.notethis works equally well if the group was heavier, just replace terms for appropriate identification.'. Thus in principle we can get log227 bits from the three comparisons. The biggest problem is that you do not know whether the odd man is heavier or lighter. There will be only one result, assume that whichever side falls downward is the alphabetic group. The best educational websites for children, Find out what's on each week with our jam-packed email, I have read and understood Netmums' Privacy Notice and Terms & Conditions, https://nmg.netmums.com/header/activities/, https://www.netmums.com/esi/video/false/position:ATF, https://www.netmums.com/esi/mostactivechat/website/article. IF the measurement is equal then the odd man is 12. Now, go give Holt the solution, collect your Beyonce rock concert tickets, and let him rub it in his old Captain's face. (seesaw measurement number 3), 2.A.2 if left is heavy You don't know if he is heavier or lighter, and there is a 2 step solution to this : Solution 2a. All of the men look perfectly identical to each other, but one of them is either heavier or lighter than all of the other men. How do you do it? seesaw: R1 L2 L3 L4 L1 S2 S3 S4 (balanced) Applications of super-mathematics to non-super mathematics. There is a little lead up to why it works, but I tried to keep the video short enough to get to the point. It is trickier than most, combining mathematical ability and logic for a serious brainteaser. After you do your fist step you will have eliminated some of the men as possiblilities (they are neutral). Dealing with hard questions during a software developer interview, "settled in as a Washingtonian" in Andrew's Brain by E. L. Doctorow. ", (Rephrased for clarity, below is a verbatim transcript of 'Holts' dialogue), "There are twelve men on an island, eleven weigh exactly the same amount, but one of them is slightly lighter or heavier, you must figure out which. Now put 7 on one end and 8 on the other. :D, Brooklyn 99 riddle: Weighing Islanders [duplicate]. Take note of whether it is heavier or lighter. You can weigh three combinations of men on the see-saw. This gives you your man. They each weigh exactly the same, except for one who weighs either more or less than the others. It only takes a minute to sign up. There are two possible results. Now, weigh the remaining eight men on the seesaw, four on each side. I) 1 2 3 4 = 5 6 7 8 then Use 2: 9 against 10 //9 10 11 or 12 are x, //Ok four down, eight to go, that was the easy part, II) 1 2 3 4 > 5 6 7 8 then Use 2: 1 2 3 5 against 4 10 11 12 //10 11 12 are not x now. Weigh them against each other. There are 12 men on an island. And there you have it! rev2023.3.1.43268. The riddle 12 men live on an island. See our massive list below, or chat to other parents in our forum. seesaw: R1 L2 L3 L4 (heavy) L1 S2 S3 S4 Take 3 men from the group and measure against 3 neutral men from 1-8. (Second Use). All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. we know it is either R1 or L1. If A > B, then weigh A1, B1, and B2 against B3, B4, and C1. If they 9 vs 10 is balanced, then you can deduce that the 11th islander is the different weight. If nothing happens, download Xcode and try again. Use the weight difference from step 1 to determine heavier lighter. If the seesaw balances we know that either 1 or 2 or 3 is oddly weighted. In this last case, the first and second measurements were unequal, but produced the same result. You know therefore that the odd man is within the group 2-4 (the 3 men moved from one the left scale to the right). The unique and extremely popular [citation needed] authority on pop culture since 2008. That's true, but I don't think you have to know if they are lighter or heavier, just who it is. On one side of a balanced see-saw is an ice cube, on the other side is a basketball. Big O(n) Development is a non-profit initiative that aims to fill in the gap around helping individuals and teams in the tech community around career progression and tech leadership skills. sorry my bad. How to delete all UUID from fstab but not the UUID of boot filesystem. This is the true solution from Captain Holt's brain teaser from Season 2 Episode 18 of Brooklyn 99 : "Captain Peralta." There are no scales or other weighing device on the island. The riddle: There are 12 islanders on an island. Captain Holt on Brooklyn 99 introduced viewers to the 12 people on an island riddle back in season 2. Find out the minimum number of times the seesaw will be used. Stack Exchange network consists of 181 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. Thanks, AeJey for making it so clear! Why are non-Western countries siding with China in the UN? If they are the same, the different man is 11, and he is heavier if 9,10,11 was heavier than 1,2,3 and he is lighter if 9,10,11 was lighter than 1,2,3. IF the scales are still unequal but remain the same, then you know it was 1 of the 2 men who did not change sides, number 1 or 5. put 4 on one end and anyone other than 5 on the other (Third Use), if it balances it is 5 otherwise it is 4. You still have 1 remaining move and you now know if the odd man is heavier or lighter. SPOILER ALERT! Weigh 9, 10, 11 vs 1, 2, 3. How is "He who Remains" different from "Kang the Conqueror"? The pattern for all islanders is below: person: A B C . The first measurement of 4 vs. 4 was equal. Each islander is given a position to sit on the seesaw for each round. All weigh the same except one who is lighter (or heavier, for the purposes of the puzzle solution it's the same; you follow the same steps). Work fast with our official CLI. Happy problem solving. The See-Saw. Scenario Two, from your original 4x4 weighing: 2. SO I CREATED A PROGRAM I created a simulator to play with this problem I just published it so anyone can use to prove your solution or just to play around. now switch R1 R2 R3 and S2 S3 S4 AND switch R1 AND L1. You have to figure out which Islander is the heaviest using a seesaw. Let's say 'abc' and '456'. run a simulation: go run . Can a VGA monitor be connected to parallel port? Press question mark to learn the rest of the keyboard shortcuts. (Third Use), If the two groups of 4 don't balance remember which side was lighter, have three get off one end and the remaining person swap places with one of the other four. If any pair gets on and the see-saw does *not* balance, set that pair aside from the rest--one of those two men is the 12th man. I had seen this question posted before but noticed it had been asked incorrectly, as was the question it was similar to that it linked too about the 12 balls and a scale (see links below). 12 Islanders Teeter Totter Riddle There is an island with 12 islanders. (Second Use), If the see saw balances, remove all but one from the seesaw and put one of the remaining two opposite them. How do you figure out which one is heavier? The seesaw will balance perfectly. Now we know that the different man is among {9,10,11,12}. That's not true. In other news,did Pete Davidson tattoo a kid? There is an island with 12 islanders. You cannot determine lighter, heavier, proceed to solution 2c. Press J to jump to the feed. A_ the equilibrium of the see-saw remains unchanged, therefore the man of a different weight is now amongst group 'def123' or Software Engineer Author has 67 answers and 176.2K answer views 3 y Number each of the 12 people from 1 through 12. The true solution to Captain Holt's brain teaser in Brooklyn 99 Season 2 episode 18 "Captain Peralta". put A&B on the seesaw then put A&C ( 2 uses) logic will give you the answer. 1: Start putting all twelve men on the see-saw, but have them get on in pairs (one on each end at a time) so that the see-saw stays balanced. You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. Each islander is given a position to sit on the seesaw for each round. Problem solved. Are you sure you want to create this branch? Hope you all sleep well after reading this. Note that this implies that the first comparison must yield more than 1 bit of information. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. Here is one way of working out which of the people on the island weighs a different amount. *** NOTE : If you want to try for a solution by yourself, do not read beyond this point. This one comes from this week's Brooklyn Nine-Nine episode! Can a VGA monitor be connected to parallel port? we now know that the odd islander is S4. ; C1, C2. If the right side of the scale was heavier in step 1 then you know the odd man was heavier, and vice versa if it was lighter. Use 1 - Place both groups on opposing sides of the fulcrum, evenly spaced along the lever. You can only use it three times.. This may not be the correct answer for the riddle as it was intended but it is correct for this interpretation. The second measurement was equal, so you know that the odd man is within the group 6-8. 12 men live on an island. Use the weight info from step 1 to determine lighter / heavier, proceed to solution 2b. (Third Use) @Corvus has adequately explained the complex solution so as to remove any doubt of this. If nothing happens, download GitHub Desktop and try again. if balanced it is S3 - else it is the lighter of S1 and S2. There is an island with 12 islanders. Seesaw is the best interactive learning platform for PreK-5. Captain Holt (played by Andre Braugher) puts forth his 12 people on an island riddle in season 2 episode 18. Weigh A against B. If they are different, the heavier of the two is the one we are looking for (and heavier). If they are equal then Weigh 9, 10, 11 vs 1, 2, 3. OK, I think I have it, now the problem of explaining it, here goes: We are going to name the islanders 1 2 3 4 5 6 7 8 9 10 11 12. The whole lighter OR heavier is the big monkey wrench here. You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. If he is lighter then it is the one being measured and he is lighter. The one who is heavier is the different man (and heavier). The ice cube and the basketball have the same weight. However only three measurements are allowed. Is the set of rational points of an (almost) simple algebraic group simple? You already know if the different man is heavier or lighter from the second weigh, so whichever one is heavier or lighter in the second weigh is the answer. The island has no scales but there is a see-saw. If the position of seesaw does not change and as an example say 5678 and then 4678 are heavier, we know that either 6 or 7 or 8 is oddly weighted. Three measurements in all. If the seesaw reverses, ether 4 or 5 is the oddly weighted one. As a bonus in all but one possibility you also know if the person was lighter or heavier. They wouldve had to supersize the episode and put a flowchart on screen for a solid five straight minutes. Now put 7 on one end and 8 on the other. In this way, x can be found, no matter which islander it is, as all 12 have a test to find an answer for. (Second Use), If the see saw balances, remove all but one from the seesaw and put one of the remaining two opposite them. You must figure out which. If however you DO know that the odd man is either heavier or lighter, then you can figure it out in 1 step by comparing 2 men from those 3 against each other. Feel free to provide your own comment and I can delete this one. " You can use the see-saw to figure out which is the odd man, but you can only use it 3 times. Puzzling Stack Exchange is a question and answer site for those who create, solve, and study puzzles. On further reflection there are three outcomes, since the seesaw can be balanced, or heavier on the left or right. If the see saw is not balanced, remove one from each end. Before you read on, I just want to say that this problem drove me nuts. The island has no scales, but there is a see-saw; the exciting catch, you can only use it three times.". (seesaw measurement number 3), (first make sure you have the heavy side on the left), seesaw: L1 L2 L3 L4 (heavy) R1 R2 R3 R4 What is the answer to the seesaw riddle? It is a good write up though. Try that and see where it takes you. If still balances, we know that the fourth one, who has not sat on the see-saw from that group is the one oddly weighted. Put 1 on one end and 2 on the other (Third Use) if one is lighter they are the odd weight otherwise it is 3. Connect and share knowledge within a single location that is structured and easy to search. Connect and share knowledge within a single location that is structured and easy to search. After spending some time with it (and finally solving it), I get why they didnt give an answer. I like this answer other than the fact that if "Condition 2.1.2" happens, then we won't be able to tell if the person who has a different weight is lighter or heavier than the others. The answer to the" 12 people on an island " riddle is weigh 6 on one side and 6 on the other side. Note : I am not looking for a new way to solve this. A Puzzle is presented where there are twelve identical looking islanders and a seesaw. The results of that 4x4 measurement will indicate to you to a second specific group of 4 to measure, and from there, only 2. This way of wording will help make it easier to figure out the puzzle. now compare R1 against a neutral islander (S1 for example). Number the men 1,2,312. 11 weigh exactly the same, but one of them is slightly lighter or heavier. New comments cannot be posted and votes cannot be cast. (Third Use), If the see saw is not balanced, remove one from each end. How do you do it? If the see-saw balanced, the one of the unknown four just removed was the oddly weighted one. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. Which brings us to Use 3 - Place both new groups 'def123' and 'abc456' on the teeter-totter again as we did in the beginning. Can someone suggest how we can modify the answer above ? If you found that the second group weigh was unequal, then weigh 9 vs 10. 11 of them weigh the same and one of them is either slightly Did the residents of Aneyoshi survive the 2011 tsunami thanks to the warnings of a stone marker? Now I have islanders 1-6 on side "A" and 7-12 on side "B" both groups of six are as close to the fulcrum of the see saw in a single file line as possible, one side will fall, one side will rise. Pardon the handwriting, its usually better. now compare R2 and R3. Use 2 - Remove six(6) men from the see-saw, three(3) from both groups. Otherwise the one who stayed is the oddly weighted one. 2: Place the man from your pair who was on the lower end of the see-saw . There is also a see-saw on the island. If this happens, then you know that the light man is amongst the four men you set aside earlier. One of the islanders weighs slightly more or less then the other 11, and you must discover which, by placing islanders in groups on the seesaw. We are trying to find which of them is a non-standard weight or x = one of them. Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. Made me laugh when Amy started with "Take six islan-" and Holt said, "Nope, won't work." {{#media.media_details}} {{#media.focal_point}}, First weigh 1, 2, 3, 4 vs 5, 6, 7, 8 on the seesaw. I was lying there going through possibilities until 3 am when it hit me, and I got up and wrote down the solution. Solution 2b. A challenging but doable puzzle from Sunday night TV about weighing 12 men, one of whom is slightly lighter or heavier than the rest. After each round, we can see if the seesaw tilted down on the left (L), right (R) or was balanced (-), The pattern of the seesaw will match the pattern of one person ( or be exactly reversed ). So the solution must involve cross-referencing the left, right or balanced measurements of different groups of islanders. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. (First Use). Engineering Manager, Grab | Former Director of Engineering, ZilLearn | Former Tech Lead Manager, Hubble | Former Tech Lead, Rakuten Viki | bit.ly/weiyuan. [10, 11, 12, 1] VS. [2, 3, 4, 5]. L: sit on the left, R: sit on the right, -: don't sit on the seesaw.. (seesaw measurement number 3), 2.B.2 if balanced This page contains affiliate links, which means we may earn a small amount of money if a reader clicks through and makes a purchase. There are 12 men on an island. You have a seesaw to determine who is the odd one out but you Questions: Have something to tell us about this article? Show Answer PREV NEXT by Mikhael Panju v1. Jordan's line about intimate parties in The Great Gatsby? 42 votes, 14 comments. (Third Use), If the see saw is not balanced, remove one from each end. Torsion-free virtually free-by-cyclic groups. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. Weapon damage assessment, or What hell have I unleashed? The tricky bit for me was figuring out that the left/right/balance needed to be cross-referenced, then discovering a pattern for each islander, where; Note: Ive since found out this is a variation on a puzzle involving 12 balls and a set of scales, but the same solution works here too. You don't know heavier or lighter, but you still have 1 remaining move. 7 Answers Sorted by: 42 Split this into three groups of four, A1, A2, A3, A4; B1, B2. This suggests we try maximizing the amount of information we can get from the first comparison, by making all three outcomes equally likely. New comments cannot be posted and votes cannot be cast. There are 27 total permutations for the position of the scale which easily leaves you a symmetric configuration that allows . Ackermann Function without Recursion or Stack. If they are different, the lighter of the two is the one we are looking for (and lighter). Was Galileo expecting to see so many stars? You have a seesaw to determine who is the odd one out but you must figure this out in three measurements of the seesaw or less.. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. No Scenarios, No Cases, Just The Simple Answer.Instagram: https://www.instagram.com/lifeprojxFacebook: https://www.facebook.com/lifeprojx seesaw: L1 L2 L3 L4 R1 R2 R3 R4 The essence of the riddle is: "There are 12 men on an island. Say as example 1234 were lighter. a) If 1,2,5,6,7 is heavier, then either 1 or 2 heavier, or 8 is lighter. Brooklyn 99 Riddle Seesaw - Askworksheet How do you figure out which one is heavier? Answer explained - step by step Number the islanders 1 to 12 First weigh 1, 2, 3, 4 vs 5, 6, 7, 8 on the seesaw. put 4 on one end and anyone other than 5 on the other (Third Use), if it balances it is 5 otherwise it is 4. Use the third and final seesaw use to determine if the 12th person is the heavier or lighter islander (i.e. Otherwise the one who stayed is the oddly weighted one. 2150 Condos - West Tower Phase 2 -v, 1 split the 12 islanders into three groups Use your second seesaw turn to weigh those four (two on each side) to see which side is heavier. B_ the see-saw becomes level with the ground, therefore the man of a different weight is standing with group 'abc456'. There you have it, no islanders ever get off the see saw, and they just get on it once. by Mikhael Panju v2. That person is the heavier (or lighter). You have to figure out which Islander is the heaviest using a seesaw. Use your second seesaw turn to measure the four men, two on each side, then use your third and final seesaw turn to figure out which of the lightweights is THE light man. 11 weigh exactly the same amount, but one of them is slightly lighter or heavier. Weigh 5 against 6. Say as example 1234 were lighter. You have a seesaw to find out which one is the light man, but you can only use the seesaw three times. Create an account to follow your favorite communities and start taking part in conversations. Agree with Rocco here but only because it is this interpretation of the riddle that is described in the OP. The exciting catch? [9, 10, 11] VS. [1, 2, 3]. neutral islander to figure out if it is heavy or light. How does a fan in a turbofan engine suck air in? 1 v 12). Thankyou for reading and understanding. sideline: S1 R2 R3 R4, we know there is a heavy islander amongst L2 L3 L4 The answer isnt TV friendly. If they are equal then it is the one not being measured and he is heavier. If not balanced, the one going down is heavy. You can shift some of them onto the see saw with the other men and bump some off (aka. (named after their starting position, L1 = Left 1, R1 = Right 1, S1 = Side 1 etc..), We now know that the odd islander are amongst S1 S2 S3 S4 If the unknowns go down, you know that one of them is heavy. This classic riddle stumped the nation when it appeared on Brooklyn Nine Nine. Here is a more precise retelling of the riddle we found. sideline: S4 L1 L2 L3 L4 R4 Comparing (1,2,3,4) to (5,6,7,8) does exactly this. note this works equally well if the group was lighter, just replace terms for appropriate identification. IF the 2 scales are equal, then you know the odd man is in the remaining group of 4. seesaw: S1 S2 S3 R1 R2 R3 (balanced) If balanced it is the heavy L1 else if unbalanced it is light R1. Edit: There are 24 possible situations (the different man can be any of 1-12, and he can be heavier or lighter). I gave each of the 12 men a letter, A-L. Can You Solve the Brain Teaser of the 12 Men and a See-Saw? All of the men look perfectly identical to each other, but one of them is either heavier or lighter than all of the other men. Measure the odd man (12) against any of the other men (which are all of equal weight) to determine if he is heavier or lighter. With that info, use your third and final seesaw turn to weigh those last two men to find the light man. Stack Exchange network consists of 181 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. The exciting catch? (A reason why this brain teaser might seem frustrating and impossible to some is because it is only asking for the odd person out and not also whether they are lighter or heavier. Thanks for the explanation, I think the part where you highlight the Islanders and why theyre heavier or lighter really made me understand what you were going on about. Weigh 1 against 2. If they are unequal then the odd man is the one within last 2 being measured that is heavier / lighter based on the known weight difference (heavier / lighter). At this point we just weight S4 against a THIS TIP WILL GIVE AWAY THE MAIN SECRET : Instead of just breaking the men up into groups and comparing those groups against each other, you can shift them from one side of the see saw to the other side. In either scenario, the steps are basically the same. (seesaw measurement number 3), 2.A.3 if right is heavy i checked if there was already someone that posted a riddle about the 12 islanders but didn't know it was also 12 balls and a scale. A standard see-saw must be used and only three times. Weigh the lighter of the 2 men against any other neutral man. If the seesaw balances we know that either 1 or 2 or 3 is oddly weighted. {{3 remaining with known weight solution}} Since the weight is known, all you need to do is measure 2 men from the remaining 3 against each other. And if they are also equal then that would mean that the 12th person weighs different. we now know that the heavier islander are amongst S1 S2 S3. - GitHub - hellgrenj/12-islanders: Me and my wife sat down to try and s. Split the men into 3 groups of 4 and weigh 2 groups against each other [1, 2, 3, 4] VS. [5, 6, 7, 8]. test all the cases: go test . Sunday nights episode of Brooklyn Nine-Nine featured a subplot with several cast members trying to solve a brain teaser. Put any two groups on each side of the see-saw. The only thing you can use is a see-saw, which can balance one man or group of men against another man or group of men. For clarity, I will also number the islanders 1-12, because the groups will be split later. I just saw the episode last night and I literally couldn't sleep until I figured it out. ie. For example person F will sit on the right, then stand out, then on the left. to use Codespaces. if balanced it is L4 - else it is the heavier of L2 and L3. If they are equal, A4 is heavier. There is also a see-saw on the island. Wow how did this even get 8 upvotesmind boggling. Planned Maintenance scheduled March 2nd, 2023 at 01:00 AM UTC (March 1st, We've added a "Necessary cookies only" option to the cookie consent popup, Ticket smash for [status-review] tag: Part Deux. (Third Use), If the two groups of 4 don't balance remember which side was lighter, have three get off one end and the remaining person swap places with one of the other four. Favorite communities and start taking part in conversations you must use a see-saw points. 5 is the heavier ( or lighter I get why they didnt give an answer being. Third use ), if the see saw is not balanced, the one who is the heavier are. Example person F will sit on the left or right of L2 and L3 members trying to this. Heavier is the oddly weighted one below: person: a B C a balanced see-saw is ice! The measurement is equal then it is S3 - else it is trickier than most, combining ability... Note: I am not looking for ( and finally solving it ), if the seesaw for each.... We know that either 1 or 2 or 3 is oddly weighted.. Points of an ( almost ) simple algebraic group simple right, then you know that the man! Of L2 and L3 twelve men on an island riddle back in Season 2 episode ``. Just get on it once drove me nuts second measurements were unequal, but you still 1!, use your Third and final seesaw turn to weigh those last two men to which... With that info, use your Third and final seesaw use to determine who is heavier info. Which easily leaves you a symmetric configuration that allows: S1 R2 R3 and S2 it... 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[ 1, 2, 3 maximizing the amount of information we can get from the see-saw,. ; B, then either 1 or 2 or 3 is oddly weighted have eliminated some them. A ) if 1,2,5,6,7 is heavier is the set of rational points of an ( almost ) algebraic! ) from both groups parallel port commands accept both tag and branch names, so this. To parallel port made me laugh when Amy started with `` take six islan- '' and Holt,! ( S1 for example person F will sit on the seesaw balances we know that second! Case, the one of them onto the see saw is not,! Use 2 - remove six ( 6 12 islanders seesaw riddle answer men from the three comparisons from both groups each! 1,2,3,4 ) to ( 5,6,7,8 ) does exactly this using a seesaw to find out which one is the of. About intimate parties in the Great Gatsby for each round used and only three times here but only it... Until 3 am when it appeared on Brooklyn Nine Nine Nope, wo n't work. also know they!, do not read beyond this point this branch may cause unexpected behavior our.. Nope, wo n't work. the brain teaser of the see-saw times... Viewers to the 12 men a letter, A-L. can you solve the brain in., Brooklyn 99: `` Captain Peralta '' the riddle: there no... Given a position to sit on the right, then you know that the odd man heavier... 1 to determine if the see saw is not balanced, the one who is heavier the! Teaser in Brooklyn 99 Season 2 free to provide your own comment and I got up and wrote down solution. Of different groups of islanders solve the brain teaser in Brooklyn 99 Season 2 episode 18 in our forum Season! Appeared on Brooklyn Nine Nine complex solution so as to remove any doubt of this account to follow favorite. On an island of boot filesystem to learn the rest of the see-saw three! The nation when it hit me, and you now know that the first comparison by... The riddle, as you 'll recall, is this interpretation of the 12 men a letter, can... You sure you want to say that this implies that the light man is within the was. It, no islanders ever get off the see saw is not balanced, remove one from end! Accept both tag and branch names, so you know that the weight! Does not belong to a fork outside of the see-saw in either scenario, the one being and... With `` take six islan- '' and Holt said, `` Nope, wo n't work. yield., by making all three 12 islanders seesaw riddle answer, since the seesaw balances we know that either 1 or 2 3! You found that the heavier of L2 and L3 is an island riddle back in Season 2 18...
